Short quiz to test your understanding of the CQE body of knowledge.
 


1. Rank the following data types in order from least powerful to most powerful.
  
   1. Interval
   2. Ordinal 
   3. Ratio 
   4. Nominal 

      a 1,2,3,4 
      b 4,1,2,3 
      c 3,1,2,4 
      d 4,2,1,3



2. You are studying a transactional process that has an average error rate of 2.7%. You have
    implemented an improvement. You sample four days and find the error rates to be 2.2, 2.3,
    2.55 and 2.7. Which of the following is true? 

      a at 95% confidence there is an improvement at 97.5% there is not    
      b at 95% and 97.5% confidence there are improvements 
      c there is not an improvement at 95% and 97.5% confidence 
      d there is confidence at 97.5% but not at 95%



3. You are studying a a process that yields an average diameter of 1.503” and a standard deviation
    of .003” with a sample size of 25. What is the 99% confidence interval for the average of samples
    taken? 

      a 1.503 +/- .0012 
      b 1.503 +/- .0015 
      c 1.503 +/- .009 
      d. 1.503 +/- .003



4. On the CQE exam the average was a 74 with a standard deviation of 9. What percentage of
    students scored above a 86? 

      a 10.42% 
      b 9.46% 
      c 9.18% 
      d 8.98%



5. The alpha error is: 

      a the producers risk and can be reduced by reducing the ß error. 
      b the producers risk and can be reduced by increasing the ß error. 
      c the consumers risk and can be reduced by increasing sample size. 
      d the consumers risk and can be reduced by increasing the ß error 

For help, answers and solutions keep scrolling down

























A little help

1. one data type is go /nogo one data type is ranked ( 1= lowest, 5= highest) one data type is
    variable with no true zero (temp, calendar) one data type is variable with true zero (weight, distance)

2. one tail t test

3 use the z value for confidence with the standard deviation and sample size

4 z value

5 alpha is indirectly proportional to ß 






















answers

1. d
2. a
3. b
4. c
5. b



















Solutions to problems


1. Nominal data is go/no go, Ordinal data is ranked, Interval data is variable with no true zero and
    Ratio data is variable with
    a true zero
 
2. The average of the sample is 2.4375 and the standard deviation is .2287
     t = (2.7 – 2.4375) / (.2287/v4)
     t = .2625/.11435
     t = 2.2956 
 
    tcrit for 3df @ 95% = 2.353
    tcrit for 3df @ 97.5% = 3.182

3. confidence interval = +/- Zs/vn
    Z value for 99% under curve is 2.575
    confidence interval = +/- 2.575(.003)/5 
                                      +/- .0015

4. Z = (86-74)/9
    Z = 1.33
    Area under curve for 1.33 sigma away from mean is .0918


5. alpha is proportional to ß and is a type I or consumers risk.